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Priti
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2. both radii form a 45-45-90 triangle. the hypotnuse becomes the chord (base of the cone) which divided by 2 gives us the length necessary to solve for each side of the isoceles triangle.
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I get B too...only profound rule is the height of the triangle divides the base equally....
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Can someone draw the diagram and show ... i am still confused and couldnt understand the solution..
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Yeah finally figured it out...

I am attaching a diagram if it helps....


3/4rth the circumference of the circle = 3/4*(4*pi) = 3pi

Similarly from the figure, the total base = 2sqrt(2)
Since they are isoceles triangles, each of the sides are 3sqrt(3)

So total perimeter = 3pi + 6sqrt(3)
B for me too...
Attachments

triangle.JPG
triangle.JPG [ 6.27 KiB | Viewed 2010 times ]

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i'm still confused.

The circumference of the circle is defined as 3/4. Given the radius of 2 and C=pi2r we get a total circumference of C=4pi.

3/4 * 4pi = 3pi

How do we do calculate the base with a height of 5?



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