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Yaa my bad, median will be 6th and 7th quarter. So average 0.9 and 1.1 ie 1%
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Equilibrium point (10,5) will give you value of k from Demand curve given by P=k/Q or k=PQ=10*5=50. So we just require a and b, which are used only in supplu curve, so statement 2 is of no help. equilibrium point(10,5) substituted in supply curve equation will give one equation in a and b. We require another equation which is given by point (8,1) in statement 1. Thus statement I is sufficient...A
Both restaurants in downtown Rosemond-Sam’s Diner and the Main Street Cafe-offer a lunch special consisting of a sandwich, a dessert, and a drink for a set price. Which restaurant offers customers more choices for the lunch special? (1) The Main Street Café offers twice as many sandwich choices as Sam’s Diner. (2) Sam’s Diner has 2 more drink choices and 2 more dessert choices than the Main Street Café.
Combined..Main street has ways = 2a*x*y and Sam’s = a*(x+2)(y+2)....From this we cannot say which will be larger. say x and y are 2, then M=8a and S=16a..S>M. But say x=y=10, then M=200a while S=144a...M>S.....Answer is E
Can you please show the values of both dropdowns there? Thank you!
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curiousPope wrote:
Both restaurants in downtown Rosemond-Sam’s Diner and the Main Street Cafe-offer a lunch special consisting of a sandwich, a dessert, and a drink for a set price. Which restaurant offers customers more choices for the lunch special? (1) The Main Street Café offers twice as many sandwich choices as Sam’s Diner. (2) Sam’s Diner has 2 more drink choices and 2 more dessert choices than the Main Street Café.
Can you please post a screenshot of this question? Thank you!
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For the 3 payments you just do ($2000 + $1000 + $500) per balloon. And there 10 ballons so times it by 10 giving you $35k. So 40k - 35K is 5k
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same for 4 payments, you do ($2000 + $1000 + $500 + $250), multiplied by 10, giving you $37.5K. 40k - 37.5k is 2.5K
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Bunuel wrote:
Can you please show the values of both dropdowns there? Thank you!
In the first sentence we need a synonym of irrespection, that is "whether or not". Similarly the second statement can be derived from the first statement of the question, so they can end in a draw only if paul jr has not played.
by median method I’m getting two 50s and two 33.33s. how do I know which one wud be one. by mode metjod they are 1 and 2.
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It’s nothing but the basic application of Median and Mode: Using Mode Method: Look for the highest number (frequency) in each Rank Column from 1 through 3 Rank 1- Performer A (with 51 votes) Rank 2- Performer C (with 95 votes) Rank 3- Performer B (with 72 votes) Now, using Median Method: Each column adds up to 100 votes. So, rank assignment would be based on the answer of 50th and 51st terms Rank 1- Performer A Rank 2- Performer C Rank 3- Performer B Since we arrive at the same answer using both the methods, therefore, “Same” column of the question stem must be selected for all the ranks.
Make sure x=x , so we know that a=1, and to make ab=0 ,b must equal to 0
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The logic behind x=x? First thing I thought was that x should have a degree of 2 in order to have more than 1 solution.
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X=X means, it can have ANY number of solutions
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Any number can be equal to any number, very simple logic
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For linear equation, this was my thought process
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Notice that x/a = x - b represents a linear equation with one unknown, x. Generally, such equations have one solution for x. For instance, x/2 = x - 1, which has one solution: x = 2. Similarly, x/4 = x + 3 also has one solution: x = -4. The only way for x/a = x - b to have more solutions is if the left-hand side and the right-hand side are identical, resulting in x = x, which is true for all values of x, hence more than one solution. This could happen if a = 1 and b = 0, thereby leading to x = x, and infinitely many solutions for x.
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Hey Guys can anyone help me with this? Like how will you approach this type of question ?
In a certain company, all employees are either beta employees or standard employees. In this company, 25% of the beta employees and 17% of the standard employees participate in the voluntary equity program. Let S be the number of standard employees. If there are 600 employees total, what is the value of S?
(1) S > 100
(2) more than 130 employees participate in the voluntary equity program
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Maybe E?
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Rangerwarrior wrote:
Hey Guys can anyone help me with this? Like how will you approach this type of question ? In a certain company, all employees are either beta employees or standard employees. In this company, 25% of the beta employees and 17% of the standard employees participate in the voluntary equity program. Let S be the number of standard employees. If there are 600 employees total, what is the value of S? (1) S > 100 (2) more than 130 employees participate in the voluntary equity program
I think E As We don’t have a clear value of both parameters S and N(numbers of participants in a program) S can then take many values A+S=600 25/100A+17/100S =N
Condition 1— S>100 Condition 2 — N>130
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Bunuel wrote:
Notice that x/a = x - b represents a linear equation with one unknown, x. Generally, such equations have one solution for x. For instance, x/2 = x - 1, which has one solution: x = 2. Similarly, x/4 = x + 3 also has one solution: x = -4. The only way for x/a = x - b to have more solutions is if the left-hand side and the right-hand side are identical, resulting in x = x, which is true for all values of x, hence more than one solution. This could happen if a = 1 and b = 0, thereby leading to x = x, and infinitely many solutions for x.
Please helps me to understand what’s going wrong with my reasoning here.
X/a = X-b X= aX-ab X(a-1)= ab X= ab/(a-1)
Here the only way for X to have more than 1 solution , the denominator have to be equal to 0 Then a=1 (a-1)=0 ab/0 = infinite
And the numerator has to be different to zero to avoid 0/0( undetermined form)
as a=1 b just has to differ to zero
I don’t have a clear value of b
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Hi, can someone help me with this question?
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1(B) 2(F) is it?
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Answer given is 1C 2F
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Edoua wrote:
Please helps me to understand what’s going wrong with my reasoning here. X/a = X-b X= aX-ab X(a-1)= ab X= ab/(a-1) Here the only way for X to have more than 1 solution , the denominator have to be equal to 0 Then a=1 (a-1)=0 ab/0 = infinite And the numerator has to be different to zero to avoid 0/0( undetermined form) as a=1 b just has to differ to zero I don’t have a clear value of b
You cannot divide x(a - 1) = ab by (a - 1) precisely because (a - 1) can be 0. Hence, writing x = ab/(a - 1) would be incorrrect.
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Rangerwarrior wrote:
Hey Guys can anyone help me with this? Like how will you approach this type of question ? In a certain company, all employees are either beta employees or standard employees. In this company, 25% of the beta employees and 17% of the standard employees participate in the voluntary equity program. Let S be the number of standard employees. If there are 600 employees total, what is the value of S? (1) S > 100 (2) more than 130 employees participate in the voluntary equity program
After a thought, I realized that although the respondents supporting C in different age groups are given, total people in any range is not specified. A "No" seems apt for prompt-3 then. Is there anything else ?
Check the thread. I have given a reply on it. Otherwise n means the shows in first n years. In these n car shows the cost was 10 and 12 but after that the price increases for each regn.
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official question
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ans:3 4
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sorry. ans is 3and 3
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@chetan2u can you please help with the second part. why is it not 4?
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anyone, please help with it
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curiousPope, answer will be 3 and 3. I’ll talk of second part. The important point is common use at SAME TIME, and you can see between 1700 & 1800, there are three B, C and D together. Thus 3 techniques at same time.
Hi, If we want to have an access to the older Butler ques for the previous months like March or Feburary 2024 then how can we have it. Can anyone share the link for the same?
The links to previous butler questions are removed. They are gone! You can find them yourself, using the search box. Just put "butler" there and search!
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carcass, Thank you so much for your response. Yes, I will try to search myself by putting "Butler" in the search. Thank you!
Hi! I’m new here, not sure if I’m in the right room but I have a question for DI. Does anyone understand why X can’t be Third Street : Every Monday and Y: Second Street: Every fourth Tuesday? Thanks in advance!
Hi, thanks for the fast response. In fact, I’ve gone through that page, however, it’s still not clear for me why my answers can’t work
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hchiaki wrote:
Hi, thanks for the fast response. In fact, I’ve gone through that page, however, it’s still not clear for me why my answers can’t work
Got it. Please post your doubt there. Thank you!
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hello, i have a help please
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hchiaki wrote:
Hi! I’m new here, not sure if I’m in the right room but I have a question for DI. Does anyone understand why X can’t be Third Street : Every Monday and Y: Second Street: Every fourth Tuesday? Thanks in advance!
There was a PM too. So, I am addressing the question here itself. X has to be followed by Y. First monday is not followed by cleaning on first tuesday. Similarly, streets would be cleaned on 2nd and 3rd Monday but it will not be followed by Y. Only on fourth Monday and fourth tuesday, the cleaning of street will be done on consecutive days. Catch words are EVERY Monday and FOURTH Tuesday.
Hi Bunuel- I think answer should be C, but I am not sure. Firstly, I assumed A=x and B=3x from Statement 1 but since I do not have actual speeds, Statement 1 wasn’t sufficient to determine the time in seconds. Secondly, the average speed would not be of much help either from Statement 2. So, not sufficient Lastly, putting the two statements together and applying avg speed formula- (2*S1*S2)/(S1+S2) to get the avg speed of each wheel. Hence, concluded the both statements together are sufficient to answer the question.
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Is my approach correct?
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Also, if we solve further would the answer be 6 3/4 seconds using relative distance/relative speed concept?
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PRAGATIOSTWAL wrote:
Hi Bunuel- I think answer should be C, but I am not sure. Firstly, I assumed A=x and B=3x from Statement 1 but since I do not have actual speeds, Statement 1 wasn’t sufficient to determine the time in seconds. Secondly, the average speed would not be of much help either from Statement 2. So, not sufficient Lastly, putting the two statements together and applying avg speed formula- (2*S1*S2)/(S1+S2) to get the avg speed of each wheel. Hence, concluded the both statements together are sufficient to answer the question.
Is my approach correct?
Yes, the OA is C. Could you please post your reasoning in the thread itself? It’s always better to post a solution in the topic rather than in the chat. Thank you.