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Re: [[x]] is equal to the lesser of the two integer values closest to non- [#permalink]
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[[-3.14]] = -4 (lesser of the two{-3 and -4}= -4)
[[-(Sqroot37)]] = -7 (lesser of the two{-6 and -7}= -7)
Adding both -4-7 = -11 ;Absolute value = 11

E = [[(Sqroot143)]] = 11 (lesser of the two{11 and 12}= 11

Thus answer E
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Re: [[x]] is equal to the lesser of the two integer values closest to non- [#permalink]
Bunuel wrote:
[[x]] is equal to the lesser of the two integer values closest to non-integer x. What is the absolute value of \([[-\pi]] + [[-\sqrt{37}]]\) ?

(A) [[9.4]]

(B) [[4 pi]]

(C) \([[\sqrt{99}]]\)

(D) \([[\sqrt{120}]]\)

(E) \([[\sqrt{143}]]\)

Kudos for a correct solution.



"[[x]] is equal to the lesser of the two integer values closest to non-integer x " can be interpreted as floor(x) or round-down of x.
i.e if \(x= 3.9, [[x]] = 3\) and if\(x=-3.1, [[x]] = -4\)
so \([[-\pi]] + [[-\sqrt{37}]]\) = \([[-3.14] + [[-6.something]]\) = \(-4 + -7\) = \(-11\)

And absolute value is 11. Only E has the value when rounded down equals to 11.


+1 for kudos
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Re: [[x]] is equal to the lesser of the two integer values closest to non- [#permalink]
The value of the function is the value of integer that is left to x.
When [x] = [-pi] = [-3.14] = -4
When [x] = [-sqrt(37)] = [-6.1] = -7
[-pi]+[-sqrt(37)] = -4 -7 = -11
|-11| = 11 = required value

A. [[9.4]] = 9

(B) [[4 pi]] = 12

(C) [[99]] = 10

(D) [[120]] = 10

(E) [[√143]] = 11

E is correct
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Re: [[x]] is equal to the lesser of the two integer values closest to non- [#permalink]
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Re: [[x]] is equal to the lesser of the two integer values closest to non- [#permalink]
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