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Re: If 3^x - 3^(x - 3) = 2,106, what is the value of x? [#permalink]
guddo

Asked: If \(3^x - 3^{x - 3} = 2,106\), what is the value of x?

\(3^{x-3} (3^3 - 1) = 2106 = 2*13*3^4\)
x - 3 = 4
x =7

\(3^7 - 3^4 = 3^4 (3^3 - 1) = 3^4 *26= 2*13*3^4\)

IMO D
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Re: If 3^x - 3^(x - 3) = 2,106, what is the value of x? [#permalink]
­Hi Bunuel - I understand most of the steps but am unclear of the result when factoring. If the original equation is 3^x - 3^x-3 and you are looking to factor out the second segment (3^x-3) .. what happens to the first part? How do we end up with 3^3 - 1 ? ..... thank you
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Re: If 3^x - 3^(x - 3) = 2,106, what is the value of x? [#permalink]
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edthehead7 wrote:
­Hi Bunuel - I understand most of the steps but am unclear of the result when factoring. If the original equation is 3^x - 3^x-3 and you are looking to factor out the second segment (3^x-3) .. what happens to the first part? How do we end up with 3^3 - 1 ? ..... thank you

\(­3^x = 3^{x-3}*3^3\). So, wwhen you factor out \(3^{x-3}\) you are left with only \(3^3\).­
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If 3^x - 3^(x - 3) = 2,106, what is the value of x? [#permalink]
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If \(3^x - 3^{x - 3} = 2,106\), what is the value of x?

Since the maximum value of x is 10, which is relatively low, we can solve this problem using a units digits pattern.

The units digit pattern for powers of 3 is the following:

3 9 7 1 3 9 7 1 3 9

So, \(3^{10}\) has a units digit of 9.

Since 2,106 has a units digit of 6, we can now check to see which units digits are 3 apart that have a difference of 6.

9 - 7 = not 6

3 - 9 = not 6

1 - 3 = not 6

7 - 1 = 6

So, counting the units digits from the left to the second 7, we find that x = 7

A. 10
B. 9
C. 8
D. 7
E. 6­


Correct answer: D­
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If 3^x - 3^(x - 3) = 2,106, what is the value of x? [#permalink]
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