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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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It has to be A...

C = (100000*p)/100-p
Here we can check puuting the values for 90 and 80 i.e.

Let 100000 be x so
for 90 its => 90x/10 =>9x ----1

for 80 its => 80x/20 =>4x ------2

Now , subtracting 2 from 1 we get => 9x - 4x = 5x or 5*100000 => 500,000
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Bunuel wrote:
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

(A) $500,000
(B) $100,000
(C) $50,000
(D) $10,000
(E) $5,000

Kudos for a correct solution.


The cost to remove 90 percent of the pollutant is determined by letting p = 90 in the cost formula:

100,000(90)/(100 – 90) = 9,000,000/10 = 900,000

Similarly, the cost to remove 80 percent of the pollutant is determined by letting p = 80 in the cost formula:

100,000(80)/(100 – 80) = 8,000,000/20 = 400,000

To determine how much more it costs to remove 90 percent of the pollutant than 80 percent of the pollutant, we calculate the difference of the two costs:

900,000 – 400,000 = 500,000

Answer: A
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Attached is a visual that should help. In order to solve this question correctly, you must realize that p is expressed as a percent and thus should not be converted to a decimal.
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Screen Shot 2016-12-07 at 7.14.39 PM.png
Screen Shot 2016-12-07 at 7.14.39 PM.png [ 129.25 KiB | Viewed 62911 times ]

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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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After checking the solution for this exercise, it looks quite easy. I just don't understand one thing. Why can I just plug the 90 and the 80 for p in the formula and not 90% (90/100) or 80% (80/100)?

i.e.: 100,000(90/100) / 100 - (90/100)

Thanks a lot.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Hi Bunuel ,

Why not just plug in the difference (10%) into the equation? That's what I did first but I got a wrong answer. I read Hero8888 's explanation but I don't understand.

How come getting the percent difference here will not work? For me it seems logically sound. Where does this logic go wrong here?

Thanks.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Diwabag wrote:
Hi Bunuel ,

Why not just plug in the difference (10%) into the equation? That's what I did first but I got a wrong answer. I read Hero8888 's explanation but I don't understand.

How come getting the percent difference here will not work? For me it seems logically sound. Where does this logic go wrong here?

Thanks.


Hi - the only way plugging in 10 % (difference between 90 and 80) will work is if the variable x is attached to ALL elements of the equation ...example below

A) 10 x - (4/5) x --> if you plug in 90 and 80 separately and subtract or just plug in 10 %, you will get the same answer
B) 18x + 5x ------> if you plug in 90 and 80 separately and subtract or just plug in 10 %, you will get the same answer
C) 10 x - 6x --------> if you plug in 90 and 80 separately and subtract or just plug in 10 %, you will get the same answer
D) 125 x / 6 --------> if you plug in 90 and 80 separately and subtract or just plug in 10 %, you will get the same answer

However If you have the following equation where X is not attached to the constant -- plugging in 10 % will fail
example : 100 + (x) --> if you plug in 90 and 80 separately and subtract or just plug in 10 , you will get DIFFERENT answers

Logic : when you are subtracting (90 - 80) to give you 10 % --> you are getting rid of the constant within the equation (in above case, 100 in blue color) ..when you plug in 10 %, the constant remains...

In this equation, the numerator has the x attached to it, but the 100 underline does not and thus will fail if you put in just a 10
I) 100,000 * X / (100-X)
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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ScottTargetTestPrep wrote:
Bunuel wrote:
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

(A) $500,000
(B) $100,000
(C) $50,000
(D) $10,000
(E) $5,000

Kudos for a correct solution.


The cost to remove 90 percent of the pollutant is determined by letting p = 90 in the cost formula:

100,000(90)/(100 – 90) = 9,000,000/10 = 900,000

Similarly, the cost to remove 80 percent of the pollutant is determined by letting p = 80 in the cost formula:

100,000(80)/(100 – 80) = 8,000,000/20 = 400,000

To determine how much more it costs to remove 90 percent of the pollutant than 80 percent of the pollutant, we calculate the difference of the two costs:

900,000 – 400,000 = 500,000

Answer: A


Don't we think that 90 percent means \(\frac{90}{100}=0.90\)?

Hope help from you.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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MHIKER wrote:
ScottTargetTestPrep wrote:
Bunuel wrote:
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

(A) $500,000
(B) $100,000
(C) $50,000
(D) $10,000
(E) $5,000

Kudos for a correct solution.


The cost to remove 90 percent of the pollutant is determined by letting p = 90 in the cost formula:

100,000(90)/(100 – 90) = 9,000,000/10 = 900,000

Similarly, the cost to remove 80 percent of the pollutant is determined by letting p = 80 in the cost formula:

100,000(80)/(100 – 80) = 8,000,000/20 = 400,000

To determine how much more it costs to remove 90 percent of the pollutant than 80 percent of the pollutant, we calculate the difference of the two costs:

900,000 – 400,000 = 500,000

Answer: A


Don't we think that 90 percent means \(\frac{90}{100}=0.90\)?

Hope help from you.


Solution:

“90 percent” indeed means 90/100 = 0.9; however, we can’t replace p by “90/100”” or “0.9”, each of which is equivalent to “90 percent.” Recall that the sentence describing the formula is “The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p)”. From the wording of the sentence, we see that “p percent” requires that p be the actual percent value, not its decimal or fractional equivalent.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Bunuel wrote:
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

(A) $500,000
(B) $100,000
(C) $50,000
(D) $10,000
(E) $5,000


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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
mcelroytutoring wrote:
diegocml wrote:
After checking the solution for this exercise, it looks quite easy. I just don't understand one thing. Why can I just plug the 90 and the 80 for p in the formula and not 90% (90/100) or 80% (80/100)?

i.e.: 100,000(90/100) / 100 - (90/100)

Thanks a lot.


Hi diegocml, "per cent" means "per hundred." So when I say "90 percent," I am actually saying "90/100". Thus, if you plug the number .9 into this formula, which is already formatted for a percent input (in other words, the equation itself has already taken the division by 100 into account), then it will become .9/100 = .009, which is less than one percent!

Lesson learned: if the question or formula already includes the word "percent," then don't divide by 100, because you will be dividing by 100 twice.

­I still don't get it, please help?
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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Can someone please explain why are we not taking 90/100?
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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saynchalk wrote:
mcelroytutoring wrote:
diegocml wrote:
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

(A) $500,000
(B) $100,000
(C) $50,000
(D) $10,000
(E) $5,000

After checking the solution for this exercise, it looks quite easy. I just don't understand one thing. Why can I just plug the 90 and the 80 for p in the formula and not 90% (90/100) or 80% (80/100)?

i.e.: 100,000(90/100) / 100 - (90/100)

Thanks a lot.

Hi diegocml, "per cent" means "per hundred." So when I say "90 percent," I am actually saying "90/100". Thus, if you plug the number .9 into this formula, which is already formatted for a percent input (in other words, the equation itself has already taken the division by 100 into account), then it will become .9/100 = .009, which is less than one percent!

Lesson learned: if the question or formula already includes the word "percent," then don't divide by 100, because you will be dividing by 100 twice.

­I still don't get it, please help?

­
harvinderkaurprep wrote:
Can someone please explain why are we not taking 90/100?

Check the question:

The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 80 percent of the pollutant?

­As you can see, the stem mentions "p percent" and then inquires about "90 percent" and "80 percent." Simply substitute p with 90 and 80 to obtain p = 90 and p = 80.

Hope it helps.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
­Thanks for the response! I understand now.
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
mcelroytutoring wrote:
diegocml wrote:
After checking the solution for this exercise, it looks quite easy. I just don't understand one thing. Why can I just plug the 90 and the 80 for p in the formula and not 90% (90/100) or 80% (80/100)?

i.e.: 100,000(90/100) / 100 - (90/100)

Thanks a lot.

Hi diegocml, "per cent" means "per hundred." So when I say "90 percent," I am actually saying "90/100". Thus, if you plug the number .9 into this formula, which is already formatted for a percent input (in other words, the equation itself has already taken the division by 100 into account), then it will become .9/100 = .009, which is less than one percent!

Lesson learned: if the question or formula already includes the word "percent," then don't divide by 100, because you will be dividing by 100 twice.

­Does it also apply for "%" symbol too? 
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Re: The cost C, in dollars, to remove p percent of a certain pollutant fro [#permalink]
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harshchougule wrote:
mcelroytutoring wrote:
diegocml wrote:
After checking the solution for this exercise, it looks quite easy. I just don't understand one thing. Why can I just plug the 90 and the 80 for p in the formula and not 90% (90/100) or 80% (80/100)?

i.e.: 100,000(90/100) / 100 - (90/100)

Thanks a lot.

Hi diegocml, "per cent" means "per hundred." So when I say "90 percent," I am actually saying "90/100". Thus, if you plug the number .9 into this formula, which is already formatted for a percent input (in other words, the equation itself has already taken the division by 100 into account), then it will become .9/100 = .009, which is less than one percent!

Lesson learned: if the question or formula already includes the word "percent," then don't divide by 100, because you will be dividing by 100 twice.

­Does it also apply for "%" symbol too? 

Yes, the "%" symbol and the word "percent" mean the same thing, so they are used interchangeably.
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