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Kudos owned by the user


Bunuel received 4 Kudos for post (1001^2-999^2)/(101^2-99^2)=.

GiverPostDate
Avasawang(1001^2-999^2)/(101^2-99^2)=19-Feb-2021
blairwaldorf(1001^2-999^2)/(101^2-99^2)=06-Oct-2020
allkagupta(1001^2-999^2)/(101^2-99^2)=17-Dec-2019
144144(1001^2-999^2)/(101^2-99^2)=12-Dec-2010

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