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Re: Quant Question of the Day Chat [#permalink]
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Data Sufficiency Butler: April 2024
April 16DS 1DS 2
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Re: Quant Question of the Day Chat [#permalink]
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Problem Solving Butler: April 2023
April 16PS 1PS 2
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Re: Quant Question of the Day Chat [#permalink]
hi guys, how do we solve this?
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Re: Quant Question of the Day Chat [#permalink]
U can assume easy values to solve this.
Let’s say, brand B costs 100 rupees and mileage is 10km. Per km cost is 10 rupees
Brand A will cost 150 rupees and mileage will be 25 km. Per km cost will be 6 rupees.
So 40% less cost
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Re: Quant Question of the Day Chat [#permalink]
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Re: Quant Question of the Day Chat [#permalink]
Hi , Is there anywhere for free where I can practice topic wise quant other than overall mocks. Any separate topic wise test options ?
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Re: Quant Question of the Day Chat [#permalink]
srijasinha wrote:
Hi , Is there anywhere for free where I can practice topic wise quant other than overall mocks. Any separate topic wise test options ?

You can use forum quiz for that.
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Re: Quant Question of the Day Chat [#permalink]
what is the remainder when (12^91 + 14^91) is divided by 169?
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Re: Quant Question of the Day Chat [#permalink]
0? (what I got!). Happy to be corrected if I messed up somewhere.
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Re: Quant Question of the Day Chat [#permalink]
26?

Sorry the remainder I took for the 12 91 and 14 91 was wrong the answer should be 2
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Re: Quant Question of the Day Chat [#permalink]
Hmm. We all got different answers. Hope Rahul shares the official answer soon! :)
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Re: Quant Question of the Day Chat [#permalink]
ratpat wrote:
U can assume easy values to solve this. Let’s say, brand B costs 100 rupees and mileage is 10km. Per km cost is 10 rupees Brand A will cost 150 rupees and mileage will be 25 km. Per km cost will be 6 rupees. So 40% less cost

40%, easy with plug ins
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Re: Quant Question of the Day Chat [#permalink]
My solving of this one. I am not sure gmat typically tests binomial expansion though.
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Re: Quant Question of the Day Chat [#permalink]
it has a basic trick like (a-b)^3 + (a+b)^3 = a3 + a3 = 2 a3. similarly (13-1)^91 & (13+1)^91 has odd powers, so only 13^x numbers will remain. where x < 2, so 13^x /13^2 will leave 0 as x >2.
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Re: Quant Question of the Day Chat [#permalink]
Quick DS question:
Is z even?
1) 3z = even
2) 5z = even
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Re: Quant Question of the Day Chat [#permalink]
T4Star wrote:
Quick DS question: Is z even? 1) 3z = even 2) 5z = even

Odd*even= even
3*z=even; 5*z=even

3and 5 are odd
For the product to be even Z must be even
Answer D

It isn’t the appropriate group
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Re: Quant Question of the Day Chat [#permalink]
Added a question on the DS forum :)

Edoua wrote:
Odd*even= even 3*z=even; 5*z=even 3and 5 are odd For the product to be even Z must be even Answer D It isn’t the appropriate group

Z can be a fraction too...
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Re: Quant Question of the Day Chat [#permalink]
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