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In a certain nursery, 15 percent of the plants developed a fungus and

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In a certain nursery, 15 percent of the plants developed a fungus and [#permalink] New post   08 Jul 2023, 01:29
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In a certain nursery, 15 percent of the plants developed a fungus and died. If 40 percent of the plants that developed the fungus did not die, what percent of the plants in the nursery developed the fungus?

A. 25%
B. 27%
C. 35%
D. 40%
E. 55%
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Re: In a certain nursery, 15 percent of the plants developed a fungus and [#permalink] New post   08 Jul 2023, 03:22
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houston1980 wrote:
In a certain nursery, 15 percent of the plants developed a fungus and died. If 40 percent of the plants that developed the fungus did not die, what percent of the plants in the nursery developed the fungus?

A. 25%
B. 27%
C. 35%
D. 40%
E. 55%


We can use a 2*2 matrix to jot down the information. Assume there are 100 plants in the nursery.

15 percent of the plants developed a fungus and died

Number of plants that developed a fungus and died = 15

40 percent of the plants that developed the fungus did not die

Assume that the number of plants that developed a fungus = x

40% of 'x' did not die ; therefore, 60% of 'x' died.

This 60% is the 15 plants that died.

\(\frac{60}{100} * x = 15\)

\(x = 25\)

Required percentage = \(\frac{25}{100} * 100 = 25\)%

Option A
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Re: In a certain nursery, 15 percent of the plants developed a fungus and [#permalink] New post   09 Jul 2023, 17:36
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houston1980 wrote:
In a certain nursery, 15 percent of the plants developed a fungus and died. If 40 percent of the plants that developed the fungus did not die, what percent of the plants in the nursery developed the fungus?

A. 25%
B. 27%
C. 35%
D. 40%
E. 55%


If N is the total number of plants in the nursery and f is the number of plants that developed the fungus, we have:

# fungus & died = 0.15N

# fungus = f

Since 40 percent of f did not die, 60 percent of f did die.

# fungus & died = 0.6f

It must be true that:

0.6f = 0.15N

f/N = 0.15/0.6 = 1/4 = 25%

Therefore, 25% of the plants in the nursery developed the fungus.

Answer: A
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Re: In a certain nursery, 15 percent of the plants developed a fungus and [#permalink] New post   11 Jul 2023, 10:45
2x2 matrix

---Die--ND---Total
F--15---10---25
NF--()---()---75
total-- ()--()---100
option A 25%


houston1980 wrote:
In a certain nursery, 15 percent of the plants developed a fungus and died. If 40 percent of the plants that developed the fungus did not die, what percent of the plants in the nursery developed the fungus?

A. 25%
B. 27%
C. 35%
D. 40%
E. 55%
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Re: In a certain nursery, 15 percent of the plants developed a fungus and [#permalink] New post   08 Apr 2024, 08:13
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houston1980 wrote:
In a certain nursery, 15 percent of the plants developed a fungus and died. If 40 percent of the plants that developed the fungus did not die, what percent of the plants in the nursery developed the fungus?

A. 25%
B. 27%
C. 35%
D. 40%
E. 55%

­15% of Total => developed fungus and died.
40% of plants that developed fungus did not die => 60% of plants that developed fungus DID die

So 15% of Total = 60% of plants that developed fungus
Plants that developed fungus = 1/4 * Total = 25% of Total

Answer (A)

Check this video on percentages: 
https://youtu.be/HxnsYI1Rws8
 
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Re: In a certain nursery, 15 percent of the plants developed a fungus and [#permalink]
08 Apr 2024, 08:13
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