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At a certain fast-food restaurant, each sandwich costs x
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26 Nov 2006, 07:39
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At a certain fast-food restaurant, each sandwich costs x dollars and each dessert costs y dollars. If $50 is enough to buy 7 sandwiches and 3 desserts, is $50 enough to buy 5 sandwiches and 5 desserts instead?
(1) $50 is enough to buy 6 sandwiches and 4 desserts.
(2) $50 is enough to buy 3 sandwiches and 7 desserts.
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Re: At a certain fast-food restaurant, each sandwich costs x
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27 Nov 2006, 10:03
At a certain fast-food restaurant, each sandwich costs x dollars and each dessert costs y dollars. If $50 is enough to buy 7 sandwiches and 3 desserts, is $50 enough to buy 5 sandwiches and 5 desserts instead?
(1) $50 is enough to buy 6 sandwiches and 4 desserts.
(2) $50 is enough to buy 3 sandwiches and 7 desserts.
(1) 7S+3D=6S+4D=> S=D sandwitch and desert same price
so 50$ should be wnough to buy 5S and 5D
(2) 3S+7D=7S+3D=> S=D sandwitch and desert same price
so 50$ should be wnough to buy 5S and 5D
Answer D
Re: At a certain fast-food restaurant, each sandwich costs x
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27 Nov 2006, 10:13
I agree with hsampath: Ans B.
Let the price of a sandwich be S and a dessert be D.
From 1 and stem: 7S+3D<=50 (1) and 6S+4D<=50 (2). let (1)-(2) we have S-D <=0 this means that the price of a sandwich is less than that of a dessert. So, we can not tell for sure if we can by 5S and 5D for $50 or less.
From 2 and stem: setting up the 2 equations: we still have S<=D. but this time, since we can use $50 to buy 3 S and 7D and S<=D, we know that we can use the amount we pay for the 2D and buy 2 extra S and have enough money. Thus, Suff.
Re: At a certain fast-food restaurant, each sandwich costs x
[#permalink]
27 Nov 2006, 10:20
kevincan wrote:
At a certain fast-food restaurant, each sandwich costs x dollars and each dessert costs y dollars. If $50 is enough to buy 7 sandwiches and 3 desserts, is $50 enough to buy 5 sandwiches and 5 desserts instead?
(1) $50 is enough to buy 6 sandwiches and 4 desserts.
(2) $50 is enough to buy 3 sandwiches and 7 desserts.
Re: At a certain fast-food restaurant, each sandwich costs x
[#permalink]
28 Nov 2006, 21:41
kevincan wrote:
Sumithra wrote:
kevincan wrote:
At a certain fast-food restaurant, each sandwich costs x dollars and each dessert costs y dollars. If $50 is enough to buy 7 sandwiches and 3 desserts, is $50 enough to buy 5 sandwiches and 5 desserts instead?
(1) $50 is enough to buy 6 sandwiches and 4 desserts.
(2) $50 is enough to buy 3 sandwiches and 7 desserts.
7s+3d10s+10d<=100 s+d<=10 Bingo!
My ans B
OA and OE
I understand why 2 is sufficient. But can someone explain to me why 1 is not sufficient? What am I doing wrong?
From stem:
7x+3y<=50-----(eqn 0)
from 1:
6x +4y<=50----(eqn 1)
multiplying eqn 0 by 6 and eqn 1 by 7 we get
42x+28y<=350
42x+18y<=300 --subtracting we get
-------------------
10y<=50 ---------eqn 3
multiplying eqn 0 by 4 and eqn 1 by 3 we get
28x+12y<=200
18x+12y<=150 --subtracting we get
-------------------
10x <=50 ----------eqn 4
Adding eqn 3 and 4 we get
10x+10y<=100
or 5x+5y<=50
Thanks
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
gmatclubot
Re: At a certain fast-food restaurant, each sandwich costs x [#permalink]